I have found a problem in applying Laplace Transform to −e−atu(−t) I am doing these steps:
=−∫+∞−∞e−atu(−t)e−stdt
=−∫0−∞e−ate−stdt
=−∫0−∞e−(a+s)tdt
=−[−1a+se−(a+s)t]|0−∞
=−[−1a+s(e−(a+s)0−e−(a+s)−∞)]
=−[−1a+s(1−∞)]
=∞
Can anyone help me why it is showing like that.I check it on internet and all the books are showing the answer is 1s+a
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