Tuesday, 11 October 2016

math - Laplace Transform of eatu(t)


I have found a problem in applying Laplace Transform to eatu(t) I am doing these steps:


=+eatu(t)estdt

=0eatestdt
=0e(a+s)tdt
=[1a+se(a+s)t]|0
=[1a+s(e(a+s)0e(a+s))]


=[1a+s(1)]


=

Can anyone help me why it is showing like that.I check it on internet and all the books are showing the answer is 1s+a




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