Saturday, 17 October 2015

image processing - Is it possible to simplify the convolution integral if the functions are non-zero in disjoint areas?




Possible Duplicate:

When convolving two functions that are constants in a region and 0 everywhere else, where does the integration start?



I have a function f(x,y) and h(x,y). f(x,y) has a value of 13 when x is between 13 and 59, and y is between 0 and 1. The function has a value of 0 everywhere else. Meanwhile, h(x,y) has a value of 1 when both x and y are between 119 and 119.


These two functions are non-zero in completely disjoint regions. Is there a way to leverage this property to simplify the convolution integral?




No comments:

Post a Comment

readings - Appending 内 to a company name is read ない or うち?

For example, if I say マイクロソフト内のパートナーシップは強いです, is the 内 here read as うち or ない? Answer 「内」 in the form: 「Proper Noun + 内」 is always read 「ない...