thermodynamics - Solubility increases as Temperature increases.. Ks increases with temperature meaning dissolving is endothermic... But what about NaOH?

Question: I was self-studying and came across some confusion across a question. My confusion lies in this: Solubility increases as temperature (T) increases, Ks increases with T, meaning dissolving is endothermic. But what about $\ce{NaOH}$?

The problem I am putting forward is more to do with the equilibrium Ks, especially using the Le Châtelier's principle. We all know that the solubility of ionic substances increases as increases in temperature. That is a fact, we don't have to argue with that. We also know that dissolving $\ce{NaOH}$ is exothermic, so we don't need to discuss that. However the two statements (observations) contradict the Le Chatelier principle, because if the dissolution of $\ce{NaOH}$ is exothermic, the solubility should decreases with increase in temperature! Why doesn't it?