Tuesday, 22 November 2016

discrete signals - What is a memory less system?


As far as I have grasped the concept is that if we are given the expression


$$y[n]=(2x[n]-x^2[n])^2\,,$$


it is a memory less system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?


And this expression is memory system because we get the negative answer for negative values of $n$, right?



$$y[n]=(2x[n]-x^2[n])\,.$$




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