Calculate the molality, molarity and mole fraction of a $\ce{CuSO4}$ in a 17% m/m aqueous solution (density of the solution is 1.367 g/mole)
I did .17 * 1.367 to find grams of $\ce{CuSO4}$
and .83 * 1.367 to find grams of $\ce{H2O}$
Then used to them calculate:
molarity = 0.00146 M
molality = 1.287 m
Mole fraction = 0.023
I'm wondering if I'm doing it right?
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